180=16x^2-3x

Solution for 180=16x^2-3x equation:

180=16x^2-3x

We move all terms to the left:

180-(16x^2-3x)=0

We get rid of parentheses

-16x^2+3x+180=0

a = -16; b = 3; c = +180;
Δ = b2-4ac
Δ = 32-4·(-16)·180
Δ = 11529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11529}=\sqrt{9*1281}=\sqrt{9}*\sqrt{1281}=3\sqrt{1281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{1281}}{2*-16}=\frac{-3-3\sqrt{1281}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{1281}}{2*-16}=\frac{-3+3\sqrt{1281}}{-32}
$